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immpy
Joined: 06 May 2017
Posts: 574
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 Posted: Thu Aug 10, 2017 8:52 pm Post subject: VH+081017 |
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Enjoy the puzzle...
| Code: |
+-------+-------+-------+
| . . . | 5 6 . | 4 . 9 |
| 2 . . | 9 . . | . . . |
| . 5 9 | . 8 . | . . . |
+-------+-------+-------+
| 8 6 . | . . . | 7 . . |
| . . . | 6 7 4 | . . . |
| . . 7 | . . . | . 5 4 |
+-------+-------+-------+
| . . . | . 3 . | 2 8 . |
| . . . | . . 6 | . . 1 |
| 7 . 1 | . 9 8 | . . . |
+-------+-------+-------+
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Play this puzzle online at the Daily Sudoku site |
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JC Van Hay
Joined: 13 Jun 2010
Posts: 494
Location: Charleroi, Belgium
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| Posted: Thu Aug 10, 2017 10:29 pm Post subject: |
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3 singles; exclusions by the solutions of the 4s, C1; 1 single
| Code: | +---------------------+-----------------------+-----------------------+
| 13 1378 38 | 5 6 1237 | 4 1237 9 |
| 2 13478 368 | 9 14 137 | 1358 1367 35678 |
| 46 5 9 | 12347 8 1237 | 13 12367 2367 |
+---------------------+-----------------------+-----------------------+
| 8 6 4 | 123 12(5) 123(59) | 7 123(9) 23 |
| 13(59) 123 235 | 6 7 4 | 138(9) 123(9) 238 |
| 139 123 7 | 8 12 1239 | 6 5 4 |
+---------------------+-----------------------+-----------------------+
| 46 9 56 | 147 3 157 | 2 8 567 |
| 3(5) 2348 2358 | 247 24-5 6 | 359 3479 1 |
| 7 234 1 | 24 9 8 | 35 346 356 |
+---------------------+-----------------------+-----------------------+
5r8c1 5r5c1
9r5c1 9r5c78
9r4c8 9r4c6
5r4c6 5r4c5 -> 5r8c1==5r4c5 => -5r8c5; stte |
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Ajò Dimonios
Joined: 01 May 2017
Posts: 339
Location: Sassari Italy
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| Posted: Fri Aug 11, 2017 8:23 am Post subject: |
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Hi everyone
| Code: |
+----------------+----------------+----------------+
| 13 1378 38 | 5 6 1237 | 4 1237 9 |
| 2 1347 36 | 9 14 137 | 58 1367 58 |
| 1346 5 9 | 1234 8 1237 | 13 12367 236 |
+----------------+----------------+----------------+
| 8 6 4 | 123 125 12359 | 7 1239 23 |
| 1359 1239 235 | 6 7 4 | 1389 1239 238 |
| 139 1239 7 | 8 12 1239 | 6 5 4 |
+----------------+----------------+----------------+
| 4569 49 56 | 14 3 15 | 2 8 7 |
| 345 2348 2358 | 7 245 6 | 359 349 1 |
| 7 234 1 | 24 9 8 | 35 346 356 |
+----------------+----------------+----------------+
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Play this puzzle online at the Daily Sudoku site
[(5-6)R7C3=(6-9)R7C1; (5)R7C3-(5)R5C3=(5-9)R5C1 and (5)R7C3-(5)R7C6=(5-9)R4C6=(9)R6C6-(9)R6C1=>contradiction 0 singles 9 in column 1=>-5R7C3=>stte.
Ciao a Tutti
Paolo |
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Ajò Dimonios
Joined: 01 May 2017
Posts: 339
Location: Sassari Italy
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| Posted: Fri Aug 11, 2017 8:24 am Post subject: |
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Hi everyone
| Code: |
+----------------+----------------+----------------+
| 13 1378 38 | 5 6 1237 | 4 1237 9 |
| 2 1347 36 | 9 14 137 | 58 1367 58 |
| 1346 5 9 | 1234 8 1237 | 13 12367 236 |
+----------------+----------------+----------------+
| 8 6 4 | 123 125 12359 | 7 1239 23 |
| 1359 1239 235 | 6 7 4 | 1389 1239 238 |
| 139 1239 7 | 8 12 1239 | 6 5 4 |
+----------------+----------------+----------------+
| 4569 49 56 | 14 3 15 | 2 8 7 |
| 345 2348 2358 | 7 245 6 | 359 349 1 |
| 7 234 1 | 24 9 8 | 35 346 356 |
+----------------+----------------+----------------+
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Play this puzzle online at the Daily Sudoku site.
Similar solution
[(6)R2C3-(6)R7C3=(6-9)R7C1; (6)R2C3-(6=5)R7C3-(5)R5C3=(5-9)R5C1 and (6)R2C3-(6=5)R7C3-(5)R7C6=(5-9)R4C6=(9)R6C6-(9)R6C1=>contradiction 0 singles 9 in column 1=>-6R2C3=>stte.
Ciao a Tutti
Paolo |
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Clement
Joined: 24 Apr 2006
Posts: 1113
Location: Dar es Salaam Tanzania
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| Posted: Fri Aug 11, 2017 5:20 pm Post subject: VH+801017 |
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| Code: |
+-------------------------+------------------------+-----------------------+
|c13 c1378 c38 | 5 6 1237 | 4 1237 9 |
| 2 c1347 c36 | 9 d14 137 | 58 1367 58 |
| 1346 5 9 | e12347 8 1237 | 13 12367 2367 |
+-------------------------+------------------------+-----------------------+
| 8 6 4 | 123 125 12359 | 7 1239 23 |
| 1359 1239 235 | 6 7 4 | 1389 1239 238 |
| 139 1239 7 | 8 12 1239 | 6 5 4 |
+-------------------------+------------------------+-----------------------+
| 4569 9-4 b56 |af147 3 a157 | 2 8 a57 |
| 345 2348 2358 | 27-4 245 6 | 359 3479 1 |
| 7 234 1 | 2-4 9 8 | 35 346 356 |
+-------------------------+------------------------+-----------------------+
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(4=175)r7c469 - (5=6)r7c3 - (6=4)r1c123, r2c23 - (4)r2c5 = (4)r3c4 - (4)r7c4 (a loop) => - 4 r7c2, r89c4; stte |
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JC Van Hay
Joined: 13 Jun 2010
Posts: 494
Location: Charleroi, Belgium
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| Posted: Sat Aug 12, 2017 10:21 am Post subject: Re: VH+801017 |
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| Clement wrote: | | (4=175)r7c469 - (5=6)r7c3 - (6=4)r1c123, r2c23 - (4)r2c5 = (4)r3c4 - (4)r7c4 (a loop) => - 4 r7c2, r89c4; stte |
Hi Clement,
Interesting loop, however
1. your hyper-condensed Eureka notation doesn't allow to simply determine all the exclusions! Instead, it is better to write your loop as the following wisiwig symmetric pigeonhole matrix based on your 10 native SIS/constraints. Because, the 10 columns are native or derived SIS/constraints, it immediately gives 5 exclusions : 4r89c4, 5r7c1, (13)r3c1. Furthermore, it contains 2 exclusion matrices excluding 1r1c6 and 4r7c2. | Code: | +---------------------+----------------------+-------------------+
| (13) (1378) (38) | 5 6 237-1 | 4 1237 9 |
| 2 (1347) (36) | 9 1(4) 137 | 58 1367 58 |
| 46-13 5 9 | 1237(4) 8 1237 | 13 12367 2367 |
+---------------------+----------------------+-------------------+
| 8 6 4 | 123 125 12359 | 7 1239 23 |
| 1359 1239 235 | 6 7 4 | 1389 1239 238 |
| 139 1239 7 | 8 12 1239 | 6 5 4 |
+---------------------+----------------------+-------------------+
| 469-5 9-4 (56) | (147) 3 (157) | 2 8 (57) |
| 345 2348 2358 | 27-4 245 6 | 359 3479 1 |
| 7 234 1 | 2-4 9 8 | 35 346 356 |
+---------------------+----------------------+-------------------+
*4r7c4*| 1r7c4 7r7c4 |
|&1r7c6& 7r7c6 5r7c6|
| 7r7c9 5r7c9|
5r7c3 6r7c3
|6r2c3 3r2c3
| 3r1c1 &1r1c1& | -> 1r7c6==1r1c1 -> -1r1c6
| 3r1c3 8r1c3 |
| 3r1c2 1r1c2 8r1c2 7r1c2 |
| 3r2c2 1r2c2 7r2c2 *4r2c2*| -> 4r7c4==4r2c2 -> -4r7c2
4r3c4 4r2c5
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V V V V
-4r89c4 -5r7c1 -3r3c1 -1r3c1
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2. it doesn't solved the puzzle stte!
JC |
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Ajò Dimonios
Joined: 01 May 2017
Posts: 339
Location: Sassari Italy
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| Posted: Sat Aug 12, 2017 11:37 am Post subject: |
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Hi Clement and JC
The singles after basics are 5 (R4C3=4, R6C4=8, R6C7=6, R7C9=7,R8C4=7).
Ciao a Tutti
Paolo |
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JC Van Hay
Joined: 13 Jun 2010
Posts: 494
Location: Charleroi, Belgium
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| Posted: Sat Aug 12, 2017 12:30 pm Post subject: |
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Hi Paolo,
In my solution, I optimized the rational basics, otherwise they would lead to 7 singles !
JC |
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immpy
Joined: 06 May 2017
Posts: 574
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| Posted: Sat Aug 12, 2017 1:39 pm Post subject: |
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Here's hoping that all of you good folks are enjoying the puzzles I have been posting. Thank you for your time and interest. I can't make much sense out of the matrices, because I am not familiar with them. Any puzzle I attempt to solve, I do with pencil and paper. It may take me longer and involve more steps, but that is my way of solving them. I like a puzzle that involves more than one step to reach being solved, but higher skilled solvers can sometimes do these in one step. Kudos to all of you that achieve that goal. This one took me 8 steps.
My path began with the X-Wing on (5) which gave me the single of (7) in r7c9, and made r8c7<>5. A two string kite (4) and multiple XY-Wings, which were interspersed with another X-Wing and a W-Wing, got me to the end.
I apologize for sucking at the eureka notation.
Thanks all......immpy. |
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Ajò Dimonios
Joined: 01 May 2017
Posts: 339
Location: Sassari Italy
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| Posted: Sat Aug 12, 2017 1:56 pm Post subject: |
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Hi JC
Sorry but what I do not understand in your solution because you started out from a matrix where the 7 in R7C9 and 7 in R8C4 (which are definitely basics) have not yet been resolved and you have instead deleted 4 in column 1 with an advanced technique (fin X-wing) with the final entry of 9 in R7C2. On the one hand, you simplified the initial matrix and made it more complicated by another. However singles after basics are 5 become 7 after fin x-wing together with another fin x-wing of 2.
Ciao a Tutti
Paolo |
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JC Van Hay
Joined: 13 Jun 2010
Posts: 494
Location: Charleroi, Belgium
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| Posted: Sat Aug 12, 2017 3:05 pm Post subject: |
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Hi Paolo, to avoid any confusion, here is my definition of basics :
Basics : application of the Sudoku puzzle "basic" rule : a candidate is (placed/excluded) if it (belongs/doesn't belong) to all the solutions either of a digit or of a unit.
Furthermore, I repeat : in the actual puzzle, I optimized them to the least number of steps before the exclusion of 5r8c5.
JC |
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Ajò Dimonios
Joined: 01 May 2017
Posts: 339
Location: Sassari Italy
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| Posted: Sat Aug 12, 2017 8:44 pm Post subject: |
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Hi JC
I think I agree with you. For this reason I think the intersection technique of a line with a box falls into this category. In cell R7C9 you can delete 5 and 6 for intersection of line 9 with Box 9 and then insert 7 into R7C9 and consequently 7 in R8C4.
I define as basic technique what sudopedia indicates singles, intersections and subsets.
I agree with http://www.sudokuwiki.org/Strategy_Families
Ciao a Tutti
Paolo |
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