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jaykay
Joined: 09 Oct 2005
Posts: 1
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 Posted: Mon Oct 10, 2005 4:55 pm Post subject: Old Puzzle Aug. 5th,2005 HELP |
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Hi,
In the 8/5/05 puzzle:
000 508 496
080 090 30#
900 304 100
067 000 000
200 000 007
000 000 560
005 701 003
008 020 710
701 803 000
I put in the 9 in row 1 column 8 and also the 7 in Row 8 column 7. When i asked for a hint. I was given 5 for # (Row 2 Column 9) I cannot figure out how this was arrived at. Any help would be greatly appreciated.
Thank you in advance. Jay Kay |
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chobans
Joined: 21 Aug 2005
Posts: 39
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| Posted: Mon Oct 10, 2005 5:10 pm Post subject: |
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| If you look at box 2(r1c4-r3c6), 2 HAS to go in row 2. The 2 at r8c5 prevents 2 from being able to fit in at r1c5 and r3c5. So you can eliminate 2 from other cells in row 2. So even though r2c9 CAN be {2,5}, you can eliminate 2 and get a 5 in that cell. |
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