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ZeroAssoluto
Joined: 05 Feb 2017
Posts: 933
Location: Rimini, Italy
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 Posted: Wed Jun 21, 2017 10:47 pm Post subject: Jun 22 VH |
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Hi everyone,
| Code: |
+-----------+-----------+---------------+
| 8 3 1 | 2 47 6 | 57 457 9 |
| 29 29 4 | 1 78 5 | 3 6 78 |
| 6 5 7 | 3 48 9 | 18 2 148 |
+-----------+-----------+---------------+
| 24 124 5 | 9 6 3 | 178 1478 1478 |
| 3 14 89 | 7 25 28 | 15 1459 6 |
| 7 6 89 | 58 1 4 | 2 359 35 |
+-----------+-----------+---------------+
| 49 489 2 | 58 359 1 | 6 3578 3578 |
| 5 7 6 | 4 23 28 | 9 138 138 |
| 1 89 3 | 6 59 7 | 4 58 2 |
+-----------+-----------+---------------+
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Play this puzzle online at the Daily Sudoku site
| Quote: | W-Wing 5,8 in r7c4, r9c8 connected by number 8 in r79c2 and -5 in r7c89 and r9c5
XY-Wing 5,8,9 in r7c4, r9c25 and -8 in r7c2 |
Ciao Gianni |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Thu Jun 22, 2017 5:25 am Post subject: |
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| Code: |
+-----------+-----------+---------------+
| 8 3 1 | 2 47 6 | 57 457 9 |
| 29 29 4 | 1 78 5 | 3 6 78 |
| 6 5 7 | 3 48 9 | 18 2 148 |
+-----------+-----------+---------------+
| 24 124 5 | 9 6 3 | 178 1478 1478 |
| 3 14 89 | 7 25 28 | 15 1459 6 |
| 7 6 89 | 58 1 4 | 2 359 35 |
+-----------+-----------+---------------+
| 49 489 2 | 58 359 1 | 6 3578 3578 |
| 5 7 6 | 4 23 28 | 9 138 138 |
| 1 89 3 | 6 59 7 | 4 58 2 |
+-----------+-----------+---------------+
|
Play this puzzle online at the Daily Sudoku site
XY-Wing (59-8) pivot r9c5=> -8r7c2
Potential Deadly Pattern (29-24-49) r247c12
1r4c2=8r7c2-(8=5)r7c4-(5=8)r6c4-(8=9)r6c3-(9=351)r6c89,r5c7=> -1r5c2 |
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Ajò Dimonios
Joined: 01 May 2017
Posts: 339
Location: Sassari Italy
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| Posted: Thu Jun 22, 2017 12:52 pm Post subject: |
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Hi everyone
My solution with one step
| Quote: | | [(5)R6C4-(5)R6C9=(5)R7C9-(5)R9C8 and (5)R6C4-(5=8 )-(8)R8C6=(8)R8C89-(8)R9C8)]=>R9C8=Ø=>-5R6C4=>stte |
Ciao a tutti
Paolo |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Thu Jun 22, 2017 5:51 pm Post subject: |
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| Quote: |
[(5)R6C4-(5)R6C9=(5)R7C9-(5)R9C8 and (5)R6C4-(5=8 )-(8)R8C6=(8)R8C89-(8)R9C8)]=>R9C8=Ø=>-5R6C4=>stte |
Paolo,
Help me understand. I think I can follow until the part I've highlighted in red.
I think it says that r8c8 or 9 is 8, then r9c8 is not 8, then I don't know what this means: R9C8=Ø and then it concludes with r6c4<>5. |
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Ajò Dimonios
Joined: 01 May 2017
Posts: 339
Location: Sassari Italy
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| Posted: Thu Jun 22, 2017 7:49 pm Post subject: |
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Hi Marty
| Quote: | | [(5)R6C4-(5)R6C9=(5)R7C9-(5)R9C8 and (5)R6C4-(5=8 )-(8)R8C6=(8)R8C89-(8)R9C8)]=>R9C8=Ø=>-5R6C4=>stte |
| Quote: | Help me understand. I think I can follow until the part I've highlighted in red.
I think it says that r8c8 or 9 is 8, then r9c8 is not 8, then I don't know what this means: R9C8=Ø and then it concludes with r6c4<>5. |
| Quote: |
The two logical chains both start from the hypothesis that R6C4 is equal to 5. Both lead to a negation, R9C8 <> 5 and R9C8 <> 8, for this reason in the cell R9C8 no candidate can be entered and is therefore empty. At this point the initial hypothesis R6C4 = 5 is certainly false. With the Ø symbol I simply wanted to indicate that the cell R9C8 becomes an empty set (set theory). |
Ciao a tutti
Paolo |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Thu Jun 22, 2017 10:26 pm Post subject: |
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| Quote: |
The two logical chains both start from the hypothesis that R6C4 is equal to 5. |
OK, I did not notice that there were two chains in there. |
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