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		| arkietech 
 
 
 Joined: 31 Jul 2008
 Posts: 1834
 Location: Northwest Arkansas USA
 
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				|  Posted: Mon Sep 03, 2012 5:14 pm    Post subject: Half M-wing |   |  
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				| I am trying to identify what a half m-wing is. The following puzzle, identified as a half m-wing, located at 
 http://www.dailysudoku.co.uk/sudoku/forums/viewtopic.php?t=2143
 
 
  	  | Code: |  	  | +----------------+----------------+----------------+
 | 59   45   1    | 47   6    79   | 2    3    8    |
 | 7    34   8    | 5    34   2    | 1    9    6    |
 | 69   36   2    | 1    8    39   | 5    7    4    |
 +----------------+----------------+----------------+
 | 156  156  39   | 247  34A  8    | 347B 16   29   |
 | 4    128  39   | 6    5    1-37 | 37   18   29   |
 | 126  1268 7    | 24   9    13D  | 34C  168  5    |
 +----------------+----------------+----------------+
 | 3    9    4    | 8    1    5    | 6    2    7    |
 | 12   12   5    | 9    7    6    | 8    4    3    |
 | 8    7    6    | 3    2    4    | 9    5    1    |
 +----------------+----------------+----------------+
 Either:
 
 1. A is <3>.
 
 Or:
 
 2. A is <4>, C is <4>, D is <3>.
 
 Any cell that sees both A and D cannot be <3>. In particular, we can take out <3> from R5C6.
 
 
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 I tried to put what I see in Eureka and get:
 
 (3=4)r4c5-r4c7=(4-3)r6c7=3r6c6 => -3r5c6
 
 This looks like the classic m-wing:
 
 (X=Y)-Y=(Y-X)=X
 
 What am I missing?
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		| Marty R. 
 
 
 Joined: 12 Feb 2006
 Posts: 5770
 Location: Rochester, NY, USA
 
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				|  Posted: Mon Sep 03, 2012 5:38 pm    Post subject: |   |  
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				|  	  | Quote: |  	  | What am I missing? | 
 
 Beats me. I'm no theoretician, but if I played and reported that move I'd call it an M-Wing. I wonder who'd correct me and say it's just a half.
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		| keith 
 
 
 Joined: 19 Sep 2005
 Posts: 3355
 Location: near Detroit, Michigan, USA
 
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				|  Posted: Tue Sep 04, 2012 9:08 am    Post subject: |   |  
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				| The original M-wing was built on the idea of a complementary pair: 
 Two cells, each XY, have the same solution, X or Y.  Let's say it is X.  Then, on either end you can add a strong link in Y:
 
 XY ..... XY = Y  or  Y = XY ..... XY
 
 and the end cells are pincers on Y.
 
 The half M-wing does not need a complementary pair.  All it needs is the following:
 
 XY ..... aXY
 
 where X in the first cell forces X in the cell containing aXY where a is any other candidates.  Then you can add the strong link on Y:
 
 XY ..... aXY = Y
 
 and the end cells are pincers on Y.
 
 It's a "half" wing because it only works one way.  There is no requirement that X in aXY has any implication for the cell XY.
 
 Over time, we've forgotten the distinction.
 
 Keith
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		| arkietech 
 
 
 Joined: 31 Jul 2008
 Posts: 1834
 Location: Northwest Arkansas USA
 
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				|  Posted: Tue Sep 04, 2012 11:33 am    Post subject: |   |  
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				|  	  | keith wrote: |  	  | The original M-wing was built on the idea of a complementary pair: 
 Two cells, each XY, have the same solution, X or Y.  Let's say it is X.  Then, on either end you can add a strong link in Y:
 
 XY ..... XY = Y  or  Y = XY ..... XY
 
 and the end cells are pincers on Y.
 
 The half M-wing does not need a complementary pair.  All it needs is the following:
 
 XY ..... aXY
 
 where X in the first cell forces X in the cell containing aXY where a is any other candidates.  Then you can add the strong link on Y:
 
 XY ..... aXY = Y
 
 and the end cells are pincers on Y.
 
 It's a "half" wing because it only works one way.  There is no requirement that X in aXY has any implication for the cell XY.
 
 Over time, we've forgotten the distinction.
 
 Keith
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 The "half" m-wing is a sis 3 like all other wings. The original must have been a sis 5?
   
 Thanks Keith
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		| Marty R. 
 
 
 Joined: 12 Feb 2006
 Posts: 5770
 Location: Rochester, NY, USA
 
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