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		| guest Guest
 
 
 
 
 
 
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				|  Posted: Tue Jan 24, 2006 12:57 am    Post subject: Jan 23rd puzzle |   |  
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				| 1_5  4_9  3_6 __3   1__   __5
 692 735  418
 536 _74  ___
 7__   ___   _34
 __4   ___   657
 25_  _4_   76_
 __7   __1  __3
 3_8  9_7  _42
 
 I am completely stuck at this point.  Does anyone know a next move?
 
 Thanks,
 
 Brad
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		| wahaha Guest
 
 
 
 
 
 
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				|  Posted: Tue Jan 24, 2006 5:45 am    Post subject: Re: Jan 23rd puzzle |   |  
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				| there is a pair of hidden (1,9) in r5c5 & r6c5 
 after that, every think will run smoothly
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		| akif Guest
 
 
 
 
 
 
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				|  Posted: Tue Jan 24, 2006 7:34 am    Post subject: Jan 23rd puzzle |   |  
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				| I was stuck at this point 
 175 489 326
 --3 1-2  -7-
 -92 73- -18
 
 536 -74 ---
 7-- --- -34
 --4 --- 657
 
 25- -4- 76-
 --7 -21 ---
 3-8 9-7 -42
 
 Can anyone hepl ??
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		| dotdot 
 
 
 Joined: 07 Dec 2005
 Posts: 29
 Location: oberseen
 
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				|  Posted: Tue Jan 24, 2006 8:51 am    Post subject: for akif |   |  
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				| Hallo akif 
 One way forward is to see that r7c4 and r7c6 between them contain 3 and 8 and nothing else, i.e. {3,8}.
 Although we don't know exactly where this 3 is, it affects what can be a 3 in box9, i.e. r7c9 can't be a 3.
 
 Having found the 3 in box9, you could continue in the same sort of vein with {1,9} in col9.
 
 By the way, you have arrived at an interesting constellation with row7 and box8.
 Because the unshared parts of row7 and the unshared part of box8 must have the same values, fitting one into the other leads directly to
 {1,9} in r7c3 and r7c9
 {5,6} in r8c4 and r9c5.
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		| Jared Guest
 
 
 
 
 
 
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				|  Posted: Tue Jan 24, 2006 6:37 pm    Post subject: multiple solutions |   |  
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				| did anybody finish this one with multiple solutions? |  | 
	
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		| Bucky Guest
 
 
 
 
 
 
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				|  Posted: Tue Jan 24, 2006 9:32 pm    Post subject: Multiple Solution |   |  
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				| Yes. My coworker and I came up with different solutions for this puzzle. Strange. 
 --Bucky
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		| geoff h 
 
 
 Joined: 07 Aug 2005
 Posts: 58
 Location: Sydney
 
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				|  Posted: Tue Jan 24, 2006 10:13 pm    Post subject: |   |  
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				| Hi there, 
 Actually, there is only one solution to this problem. If you send me what you ended up with, maybe I can help you??
 
 Cheers.
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		| alanr555 
 
 
 Joined: 01 Aug 2005
 Posts: 198
 Location: Bideford Devon EX39
 
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				|  Posted: Wed Jan 25, 2006 12:04 am    Post subject: |   |  
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				| > You have arrived at an interesting constellation with row7 > and box8.
 > The unshared parts of row7 and the unshared part
 > of box8 must have the same values
 
 This is an excellent way of explaining this logical phenomenon.
 It suggests a "visual" approach to solution rather than the
 searching for patterns within profiles held within cells.
 
 +++
 
 Line 5 was quite interesting in that the line profile started as
 (4)(7)(1235689)
 and at one point became
 (3)(4)(7) (19)(28)(56)
 with three pairs on the same line.
 Has anyone encountered FOUR pairs in the same line?
 
 +++
 
 Alan Rayner BS23 2QT
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		| Guest 
 
 
 
 
 
 
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				|  Posted: Thu Jan 26, 2006 2:40 pm    Post subject: Re: Jan 23rd puzzle |   |  
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				|  	  | wahaha wrote: |  	  | there is a pair of hidden (1,9) in r5c5 & r6c5 
 after that, every think will run smoothly
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 Thanks!!!
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		| zeigler Guest
 
 
 
 
 
 
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				|  Posted: Fri Jan 27, 2006 6:43 am    Post subject: Re: Jan 23rd puzzle |   |  
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				|  	  | Anonymous wrote: |  	  |  	  | wahaha wrote: |  	  | there is a pair of hidden (1,9) in r5c5 & r6c5 
 after that, every think will run smoothly
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 Thanks!!!
  | 
 
 same here...
 
 was hard to see it in 125689 and 1289 but once pointed out it became obvious
  (usually find such hidden pairs in rows [left-right] than in columns [up-down]) |  | 
	
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