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		| Earl 
 
 
 Joined: 30 May 2007
 Posts: 677
 Location: Victoria, KS
 
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				|  Posted: Sat Apr 04, 2009 2:09 am    Post subject: April 4 VH |   |  
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				| A long wait for a glass-jaw VH, which goes down with a single xy-wing (179). 
 Early Earl
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		| Marty R. 
 
 
 Joined: 12 Feb 2006
 Posts: 5770
 Location: Rochester, NY, USA
 
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				|  Posted: Sat Apr 04, 2009 3:44 am    Post subject: |   |  
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				| I used a Type 6 UR on 18. 
 Edited 4-4: Thanks to a PM I received I tried again and realized that I must've erred since I couldn't solve it with just the UR.
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		| cgordon 
 
 
 Joined: 04 May 2007
 Posts: 769
 Location: ontario, canada
 
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				|  Posted: Sat Apr 04, 2009 4:02 pm    Post subject: |   |  
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				| A 157 xyz wing is another one punch KO. |  | 
	
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		| Kdelle 
 
 
 Joined: 20 Mar 2008
 Posts: 59
 Location: Hudson, NH
 
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				|  Posted: Sun Apr 05, 2009 5:27 pm    Post subject: |   |  
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				| I was looking forward to a VH, but this one practically solved itself! |  | 
	
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		| Ema Nymton 
 
 
 Joined: 17 Apr 2009
 Posts: 89
 
 
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				|  Posted: Fri Apr 17, 2009 2:00 pm    Post subject: |   |  
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 Perhaps it is easy to some.
 
 I come to a point where logic cannot take me further unless I am overlooking the obvious.
 
 Using the 'Draw/Play,' the hint is to place a 9 in column 7 row 4.  My question is why?  I am able to figure the possible choices as either 9 or 1.  But either choice is as valid as the other.
 
 So why the 9?
 
 ~@:o?
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		| Marty R. 
 
 
 Joined: 12 Feb 2006
 Posts: 5770
 Location: Rochester, NY, USA
 
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				|  Posted: Fri Apr 17, 2009 4:26 pm    Post subject: |   |  
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				| Hi Ema, welcome to the forum. 
 
  	  | Code: |  	  | +------------+-----------+------------+
 | 8  6   9   | 3   2  47 | 17  157 45 |
 | 1  2   3   | 47  5  8  | 679 79  46 |
 | 45 57  47  | 9   6  1  | 8   3   2  |
 +------------+-----------+------------+
 | 39 13  5   | 8   4  2  | 19  6   7  |
 | 69 18  168 | 57  19 57 | 2   4   3  |
 | 7  4   2   | 6   19 3  | 5   19  8  |
 +------------+-----------+------------+
 | 2  9   17  | 145 3  45 | 67  8   56 |
 | 46 57  46  | 2   8  9  | 3   57  1  |
 | 35 138 18  | 15  7  6  | 4   2   9  |
 +------------+-----------+------------+
 
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 Play this puzzle online at the Daily Sudoku site
 
 At this point there is an XY-Wing 79-19-17 pivoted in r2c8 which takes out the 1 from r4c7.
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		| Ema Nymton 
 
 
 Joined: 17 Apr 2009
 Posts: 89
 
 
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				|  Posted: Fri Apr 17, 2009 4:36 pm    Post subject: |   |  
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 Thank you for the welcome; and quick response.
 
 I recognize we are talking about the same square.  But I do not understand you when you say, "an XY-Wing 79-19-17 pivoted in r2c8".
 
 FYI- I have been doing Sudoku for a long while and think I am fair at it.  But I am not sure I follow your terminology "an XY-Wing 79-19-17 pivoted in r2c8".
 
 I have worked this particular puzzle for at least a week.  I can see I am at a critical point, but cannot determine why I should pick a 9.
 
 Thanks,
 
 ~@:o?
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		| keith 
 
 
 Joined: 19 Sep 2005
 Posts: 3355
 Location: near Detroit, Michigan, USA
 
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				|  Posted: Fri Apr 17, 2009 5:27 pm    Post subject: |   |  
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				|  	  | Quote: |  	  | XY-Wing 79-19-17 pivoted in r2c8 | 
 
 Look at it this way:  The pivot cell can only be <1> or <9>.
 
 If it is <1>, the chain is 79-1-7.
 
 If it is <9>, the chain is 7-9-17.
 
 Any cell that sees both wing cells <79> and <17> cannot be <7>.
 
 Keith
 
 Last edited by keith on Fri Apr 17, 2009 7:39 pm; edited 1 time in total
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		| Ema Nymton 
 
 
 Joined: 17 Apr 2009
 Posts: 89
 
 
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				|  Posted: Fri Apr 17, 2009 7:20 pm    Post subject: |   |  
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				| . 
 
 Sorry for being so dense.
 
 Column 7 has possibilities:
 row 1 = 17
 row 2 = 679
 row 4 = 19
 Column 8 has possibilities:
 row 1 = 157
 row 2 = 79
 row 6 = 19
 
 I cannot find a way to eliminate the 1 at r4c7.
 
 Please be patient with me.  I am slow.
 
 ~@:o?
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		| keith 
 
 
 Joined: 19 Sep 2005
 Posts: 3355
 Location: near Detroit, Michigan, USA
 
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				|  Posted: Fri Apr 17, 2009 8:14 pm    Post subject: |   |  
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				|  	  | Ema Nymton wrote: |  	  | . Column 7 has possibilities:
 row 1 = 17
 row 2 = 679
 row 4 = 19
 Column 8 has possibilities:
 row 1 = 157
 row 2 = 79
 row 6 = 19
 
 I cannot find a way to eliminate the 1 at r4c7.
 
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 Are we talking about the same situation?  This is the grid I am looking at:
 
  	  | Code: |  	  | +------------+-----------+------------+ | 8  6   9   | 3   2  47 | 17@ -157 45|
 | 1  2   3   | 47  5  8  | 679 79# 46 |
 | 45 57  47  | 9   6  1  | 8   3   2  |
 +------------+-----------+------------+
 | 39 13  5   | 8   4  2  | -19 6   7  |
 | 69 18  168 | 57  19 57 | 2   4   3  |
 | 7  4   2   | 6   19 3  | 5   19@ 8  |
 +------------+-----------+------------+
 | 2  9   17  | 145 3  45 | 67  8   56 |
 | 46 57  46  | 2   8  9  | 3   57  1  |
 | 35 138 18  | 15  7  6  | 4   2   9  |
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 Take a look at the cell labelled #.  It is <7> or <9>.  Which means that at least one (or possibly both) of the cells marked @ must be <1>.  Which means you can eliminate <1> in two cells as shown by -1.
 
 I hope this helps.
 
 Keith
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		| nataraj 
 
 
 Joined: 03 Aug 2007
 Posts: 1048
 Location: near Vienna, Austria
 
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				|  Posted: Fri Apr 17, 2009 8:39 pm    Post subject: |   |  
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				| (edit April 18, 0858 GMT+2: added "click-clack" and link to the : "click-clack" aria) 
 
 Ema,
 
 you are not dense at all. Obviously you are not familiar with the xy-wing technique, so no wonder you cannot crack the puzzle. I will not give an in-depth explanation, but rather an illustration. Read up on the xy-wing, it is a most powerful tool, especially for the puzzles on this site, where it cracks some 80% of all very hards !
 
 Here - in Marty's grid - I've circled the xy-wing in red:
 
   
 3 cells with 2 candidates each, but there are only 3 candidates present in any of the 3 cells: 1,7 and 9
 
 The "wing" has a center (or "pivot") cell (r2c8: "79") and two wingtip (or "pincer") cells (r1c7: "17" and r6c8 "19")
 
 Observe that both pincer cells contain "1". We will show that a cell that sees both pincers cannot contain "1". Like, the cell r4c7.
 
 Here goes.
 
 
 Let's look at r1c7. One of the pincers. If it is 1, then ... of course r4c7 cannot be 1 (no two "1"s in the same column, right?)
 
 But if it is NOT "1", then it is 7.
 Which means r2c8 (the "pivot") is "9" and .... (ta daaaa!)
 .... r6c8 is "1" and r4c7 cannot be "1" (no two "1"s in the same box, right?). For this "click-clack" effect, it is essential that each cell in the wings "sees" the next one.
 
 So.... no matter what the solution for r1c7 is, we know that r4c7 cannot be 1.
 
 That is the magic of the xy-wing. click-clack.
 
 It works from the other side, too.
 
 If r6c8=1 then r4c7 cannot be "1".
 If r6c8 is NOT "1", then r2c8=7 (click) and then r1c7=1 (clack). Again r4c7 cannot be "1".
 
 The magic works every time you find such a wing.
 
 ___
 
 edit: Keith was quicker ....
   [url][/url]
 
 Last edited by nataraj on Sat Apr 18, 2009 7:09 am; edited 2 times in total
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		| Ema Nymton 
 
 
 Joined: 17 Apr 2009
 Posts: 89
 
 
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				|  Posted: Fri Apr 17, 2009 11:19 pm    Post subject: |   |  
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 Thank you.
 
 It makes sense.  For longer than a week, I have looked and not seen.  I have faced this issue many time when playing this 'blankety-blank- blank' game.  I have been beaten by this formation time and again.
 
 Your solutions are understandable.  Now that I know what to look for, watch out.
 
 Again thank you for the answers and your patience.
 
 ~@:o?
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		| nataraj 
 
 
 Joined: 03 Aug 2007
 Posts: 1048
 Location: near Vienna, Austria
 
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				|  Posted: Sat Apr 18, 2009 7:10 am    Post subject: |   |  
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 happy winging!
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