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keith
Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
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 Posted: Wed Jun 11, 2014 8:46 am Post subject: VanHegan 4-16200063 |
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Interesting ending. Something Danny Jones suggested a long time ago.
| Code: |
+-------+-------+-------+
| . . 2 | . 4 9 | . 7 8 |
| 9 7 . | . . . | . . . |
| 8 . 3 | . 2 7 | . . . |
+-------+-------+-------+
| . 2 . | . . 3 | 4 . . |
| . 9 . | . . . | . 2 . |
| . . 7 | 2 . . | . 1 . |
+-------+-------+-------+
| . . . | 1 7 . | 9 . 5 |
| . . . | . . . | . 8 1 |
| 7 8 . | 9 6 . | 3 . . |
+-------+-------+-------+
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Play this puzzle online at the Daily Sudoku site
Keith |
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JC Van Hay
Joined: 13 Jun 2010
Posts: 494
Location: Charleroi, Belgium
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| Posted: Wed Jun 11, 2014 9:33 am Post subject: |
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| Code: | +-----------------+-----------------+-----------------+
| 5(6) 1 2 | 3 4 9 | 5(6) 7 8 |
| 9 7 56 | 568 158 16 | 2 3 4 |
| 8 4 3 | 56 2 7 | 1 59 (69) |
+-----------------+-----------------+-----------------+
| 1 2 568 | 5678 589 3 | 4 59 679 |
| 34 9 568 | 5678 158 146 | 568 2 367 |
| (34) 5-6 7 | 2 589 (46) | 568 1 (369) |
+-----------------+-----------------+-----------------+
| 2 3 4 | 1 7 8 | 9 6 5 |
| 5(6) 5(6) 9 | 4 3 2 | 7 8 1 |
| 7 8 1 | 9 6 5 | 3 4 2 |
+-----------------+-----------------+-----------------+
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[6r8c2=6r8c1-6r1c1=6r1c9-(6=9)r3c9-(9=346)r6c169]-(6=5)r6c2; ste |
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arkietech
Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA
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| Posted: Wed Jun 11, 2014 11:22 am Post subject: |
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| Code: | *-----------------------------------------------------------*
|a56 1 2 | 3 4 9 |b56 7 8 |
| 9 7 56 | 568 158 16 | 2 3 4 |
| 8 4 3 | 56 2 7 | 1 59 b69 |
|-------------------+-------------------+-------------------|
| 1 2 568 | 5678 589 3 | 4 59 679 |
| 34 9 568 | 5678 158 146 | 568 2 367 |
| 34 c56 7 | 2 589 c46 | 568 1 c369 |
|-------------------+-------------------+-------------------|
| 2 3 4 | 1 7 8 | 9 6 5 |
| 5-6 d56 9 | 4 3 2 | 7 8 1 |
| 7 8 1 | 9 6 5 | 3 4 2 |
*-----------------------------------------------------------*
6=5)r1c1-(5=9)r1c7,r3c9-(9=5)r6c269-(5=6)r8c2 => -6r8c1; ste |
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keith
Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
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| Posted: Thu Jun 12, 2014 8:09 am Post subject: |
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After basics:
| Code: | +----------------+----------------+----------------+
|d56 1 2 | 3 4 9 |e56 7 8 |
| 9 7 56 | 568 158 16 | 2 3 4 |
| 8 4 3 | 56 2 7 | 1 59 f69 |
+----------------+----------------+----------------+
| 1 2 568 | 5678 589 3 | 4 59 679 |
| 34 9 568 | 5678 158 146 | 568 2 367 |
| 34 a56 7 | 2 589 46 | 568 1 3-69 |
+----------------+----------------+----------------+
| 2 3 4 | 1 7 8 | 9 6 5 |
|c56 b56 9 | 4 3 2 | 7 8 1 |
| 7 8 1 | 9 6 5 | 3 4 2 |
+----------------+----------------+----------------+ |
Coloring on 6: af are pincers taking out 6 in R6C9.
| Code: | +----------------+----------------+----------------+
|#56 1 2 | 3 4 9 |*56 7 8 |
| 9 7 56 | 568 158 16 | 2 3 4 |
| 8 4 3 | 56 2 7 | 1 59 d69 |
+----------------+----------------+----------------+
| 1 2 568 | 5678 589 3 | 4 59 679 |
| 34 9 568 | 5678 158 146 | 568 2 367 |
|b34 *56 7 | 2 589 a46 | 568 1 c39 |
+----------------+----------------+----------------+
| 2 3 4 | 1 7 8 | 9 6 5 |
|*56 #56 9 | 4 3 2 | 7 8 1 |
| 7 8 1 | 9 6 5 | 3 4 2 |
+----------------+----------------+----------------+ |
Extended XY-wing: ad are pincers on 6.
*# Coloring on 5. * must be 5.
Danny suggested this years ago: Pincers on 6 here make pincers on 5.
Keith |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Thu Jun 12, 2014 3:24 pm Post subject: |
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I don't know what an Extended XY-Wing is. A-b-c-d looks to be an XY-Chain and transporting the 6 from a to r1c1 solves it. Also don't understand how pincers on 6 create pincers on 5. But then, there's all sorts of stuff I don't understand.
(6=5)r1c1-r2c3=r45c3-(5=6)r6c2-(6=4)r6c6-(4=3)r6c1-(3=9)r6c9-(9=6)r3c9=>r1c7<>6
| Code: | +----------------+----------------+----------------+
|#56 1 2 | 3 4 9 |*56 7 8 |
| 9 7 56 | 568 158 16 | 2 3 4 |
| 8 4 3 | 56 2 7 | 1 59 d69 |
+----------------+----------------+----------------+
| 1 2 568 | 5678 589 3 | 4 59 679 |
| 34 9 568 | 5678 158 146 | 568 2 367 |
|b34 *56 7 | 2 589 a46 | 568 1 c39 |
+----------------+----------------+----------------+
| 2 3 4 | 1 7 8 | 9 6 5 |
|*56 #56 9 | 4 3 2 | 7 8 1 |
| 7 8 1 | 9 6 5 | 3 4 2 |
+----------------+----------------+----------------+ |
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keith
Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
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| Posted: Thu Jun 12, 2014 10:36 pm Post subject: |
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Marty,
If pincers on 6 both see cells 56, those 56 cells must be pincers on 5.
Keith |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Fri Jun 13, 2014 1:54 am Post subject: |
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| OK, Thanks, I think I understand. |
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arkietech
Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA
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| Posted: Fri Jun 13, 2014 2:18 am Post subject: |
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| keith wrote: | Marty,
If pincers on 6 both see cells 56, those 56 cells must be pincers on 5.
Keith |
What if both pincers were 6? |
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keith
Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
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| Posted: Fri Jun 20, 2014 7:49 am Post subject: |
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| arkietech wrote: | | keith wrote: | Marty,
If pincers on 6 both see cells 56, those 56 cells must be pincers on 5.
Keith |
What if both pincers were 6? |
The logic is, one or both pincers are 6. If they each see a cell 56, then one or both of those 56 cells is 5. They are pincers on 5.
There is a more subtle discussion if it is known that one, but not both, of the pincers is 6. You get into the possibility that the 56 cells are a remote pair, which is not the case here.
In this case, we know the 56 cells are the same: They must both be 5.
Keith |
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